Electrical circuit for fog lamp, starter, other circuits, help in understanding why they don't work Options

[Tom]

I have been reading up on some things that have grown dim in my mind over the years. While researching something else, I came across an eye-opener for me. Using equivalent circuits to understand what is happening in an electrical circuit that is failing or has failed. I had totally forgotten this technique. I tried it for the fog light circuit and in the process realized that many of our circuits are very similar. Like for the starter solenoid, just change the value of R1 to .9 ohms. As you can see, the connector resistance (key switch included) must be less that .9 ohms to even get 6 volts. So that means that the connectors need to be even cleaner and tighter. To clarify, if the connector resistance was 0.3 ohms and the solenoid resistance was 0.9 ohms, then the ratio of voltage across each resistance would be 25% across the connectors and 75% across the solenoid, resulting in 9 volts at the solenoid. To get the ratio, add the total resistance ( 0.3 = 0.9 ) = 1.2V and divide by the resistance of the solenoid. 0.9/1.2 = 75%. So 75% of the voltage reaches the solenoid. Just barely enough. If your 914 is at this point where the solenoid is working most of the time, just add some heat and it will stop. Heat increases resistance.
In the pics you will see the fog light circuit drawn as it is, ( well I may have missed a connection or two ), and then a simplified circuit showing the load resistance and connection resistance. As TABLE 1 shows, as the connectors start gaining resistance, the total circuit resistance increases, total circuit current decreases, and the power decreases, especially notice the power across the connector that is failing and the power across the load. As the connectors fail, the power goes down until there is almost no power or voltage being dropped across the load.
A good circuit drops 12 volts, 75 watts across the load ( the fog lamps, starter, other electrical device ), as the connector deteriorates the load drops less and less and the connector draws all or almost all ) of the voltage. When the connector gets to 8 ohms resistance, the total circuit resistance is 10 ohms and the connector is dropping 8/10s of the 12 volts. I don't thing 2.4 volts across the fog lamps will light them at all.
Another bad thing about power being developed across a connection is that they are not designed to handle heat. As Table 1 shows, at 2 ohms the load and connector share power at 18 watts each. If the failing connector is a relay socket, the heat has no where to go, so it just heat up until something melts, adding more resistance to the connection.
Maybe some of our EE members can check over my musings and see if I am off base or maybe hit on a reoccurring issue for us. I know using this info, electrical trouble shooting will be easier. If one were to use pins and jumper clips across every connector in a circuit that is on but not working, the bad connector could be found quickly. Any one that reads voltage would be dropping that voltage and the load would be getting less voltage.
Hope this will be of some help to our members,
Tom
EDIT: evidently there isn't much interest in this information. Over 190 looks and only 1 question from an interested member. Either no one is having issues or the information is too technical, even though I tried to simplify it as much as I could.
Tom

[bandjoey]

Thanks. I'll try that. Cleaned the lamps but never looked at the relay.