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brer |
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#1
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Advanced Member ![]() ![]() ![]() ![]() Group: Members Posts: 2,555 Joined: 10-March 05 From: san diego Member No.: 3,736 Region Association: None ![]() |
So last night we were working on rotational motion and all i could think about was the crank in my motor and my car going around a corner..
anyone want to help explain this to me? An object spinning at a constant speed has less acceleration at each consecutive point as you move further out from the center. acceleration being related to the radius of the rotational orbit and the constant change in directional velocity. Makes me car sick just thinking about it. (IMG:http://www.914world.com/bbs2/html/emoticons/barf.gif) |
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brer |
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#2
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Advanced Member ![]() ![]() ![]() ![]() Group: Members Posts: 2,555 Joined: 10-March 05 From: san diego Member No.: 3,736 Region Association: None ![]() |
while studying today i found the math for it.
for those who are curious the formula is Ar = (2Pi r)(2Pi r)/(T)(T)r acceleration in rotation is equal to (2Pi times the Radius) squared over (Time for 1 rotation) squared times the Radius which means, at one revolution per second, and object rotating with a one meter radius has an acceleration of 39.5 m/sec(squared) the same object rotating with a radius of 2 meters has an acceleration of 78.9 m/sec (squared) twice as much nearly! there is a radius doubled, which lowers the Ar. But the speed of the object went from 6 m/sec up to 19 m/sec which raised the Ar. that means the way i wrote it in the beginning was wrong. guess i learned something. so whats the difference between an engine with a long stroke vs. short stroke. The long stroke should have more acceleration going on, so does its lifespan reflect that? engine people know. |
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