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> learn something new everyday, and its making my head hurt
Katmanken
post Aug 19 2005, 08:30 PM
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The correct answer is it all depends on your plane of reference.

Are you in the car or out of the car? (IMG:http://www.914world.com/bbs2/html/emoticons/ohmy.gif)

One is more difficult than the other. (IMG:http://www.914world.com/bbs2/html/emoticons/sad.gif)

Don't forget the earth spins too... (IMG:http://www.914world.com/bbs2/html/emoticons/unsure.gif)

Better factor that in as well as galactic rotation and galactic drift.... (IMG:http://www.914world.com/bbs2/html/emoticons/wacko.gif)

Are you swimmy headed yet? (IMG:http://www.914world.com/bbs2/html/emoticons/drunk.gif)

Ken
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brer
post Aug 20 2005, 10:01 PM
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while studying today i found the math for it.
for those who are curious the formula is

Ar = (2Pi r)(2Pi r)/(T)(T)r

acceleration in rotation is equal to (2Pi times the Radius) squared over (Time for 1 rotation) squared times the Radius

which means,

at one revolution per second, and object rotating with a one meter radius has an acceleration of 39.5 m/sec(squared)

the same object rotating with a radius of 2 meters has an acceleration of 78.9 m/sec (squared) twice as much nearly!

there is a radius doubled, which lowers the Ar. But the speed of the object went from 6 m/sec up to 19 m/sec which raised the Ar.

that means the way i wrote it in the beginning was wrong.

guess i learned something.




so whats the difference between an engine with a long stroke vs. short stroke. The long stroke should have more acceleration going on, so does its lifespan reflect that? engine people know.
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SirAndy
post Aug 20 2005, 10:07 PM
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QUOTE (brer @ Aug 20 2005, 09:01 PM)
so whats the difference between an engine with a long stroke vs. short stroke. The long stroke should have more acceleration going on, so does its lifespan reflect that? engine people know.

if i recall correct, the long stroke got more low end torque ...

(IMG:http://www.914world.com/bbs2/html/emoticons/wink.gif) Andy
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