Tire size = 24.9"
Tire circumference = 24.9" x pi = 78.2"
Every tire rotation gives you 78.2" of travel.
A mile is 5,280'
5,280' per miles x 60 (60 mph) = 316,800' per h, which means 5,280' per minute (to achieve 60 miles in an hour).
5,280' x 12" (12 inch in a foot) = 63,360" traveled per minute.
63,360" (traveled distance in a minute) divided by the travel of each tire rotation 78.2" (tire circumference) = 810.2 tire rotation (of that tire) in a minute to achieve 60 mph.
Forester final drive 4.444 (per provided info) x 0.695 (6th gear) = 3.0885 Which means that the engine turns 3.0885 times faster than the axles (in 6th gear with that final drive).
Now, knowing we have 810.2 axle rotation to achieve to be at 60mph, and knowing the engine rotates 3.0885 faster than the axle, then: 810.2 x 3.0885 = 2501.7 which is your engine RPM.
Using this and changing the various parameters, you should be able to calculate everything.
Sorry for the math lesson...
Edit: it's not only about the final drive, it is also about the gear ratios. I am not familiar with Suby stuff, but are those final drives shown in your original post using the same gear ratios (5th or 6th gear)?