 914/4 injector, Voltage |
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| gifted914 |
 Apr 17 2013, 09:19 PM
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#1
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middleagecrisis  Group: Members Posts: 30 Joined: 17-April 13 From: Australia / Brisbane Member No.: 15,778 Region Association: Australia and New Zealand  |
G'day all.
Does anyone know the operating voltage and amps on the injector. I dont't thing it is straight 12 volts. Peter |
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Replies(1 - 7)
| Mike Bellis |
Apr 17 2013, 09:30 PM
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#2
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Resident Electrician Group: Members Posts: 8,347 Joined: 22-June 09 From: Midlothian TX Member No.: 10,496 Region Association: None 
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It is a 12V injector. The amperage is in the mili amp range. Measure the resistance and use Ohm's Law to solve for current.
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| Dave_Darling |
Apr 17 2013, 10:43 PM
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#3
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914 Idiot Group: Members Posts: 15,161 Joined: 9-January 03 From: Silicon Valley / Kailua-Kona Member No.: 121 Region Association: Northern California
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The 1.8s have the resistor pack which drops the voltage going to the injectors.
The 1.7 and 2.0 ECUs do not supply 12V, either. Hmm, actually: according to the D-jet bible, the D-jet injectors see a peak of just over 12V, and are held open by 4-5V. http://members.rennlist.com/pbanders/ecu.htm#D1-D2 --DD |
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| gifted914 |
Apr 18 2013, 01:13 AM
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#4
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middleagecrisis Group: Members Posts: 30 Joined: 17-April 13 From: Australia / Brisbane Member No.: 15,778 Region Association: Australia and New Zealand |
QUOTE(Dave_Darling @ Apr 18 2013, 02:43 PM)  The 1.8s have the resistor pack which drops the voltage going to the injectors. The 1.7 and 2.0 ECUs do not supply 12V, either. Hmm, actually: according to the D-jet bible, the D-jet injectors see a peak of just over 12V, and are held open by 4-5V. http://members.rennlist.com/pbanders/ecu.htm#D1-D2 --DD thanks (IMG:style_emoticons/default/beerchug.gif) |
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| gifted914 |
Apr 18 2013, 01:13 AM
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#5
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middleagecrisis Group: Members Posts: 30 Joined: 17-April 13 From: Australia / Brisbane Member No.: 15,778 Region Association: Australia and New Zealand |
QUOTE(kg6dxn @ Apr 18 2013, 01:30 PM) It is a 12V injector. The amperage is in the mili amp range. Measure the resistance and use Ohm's Law to solve for current. Thanks (IMG:style_emoticons/default/beerchug.gif) |
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| sofi2t81 |
Apr 18 2013, 08:48 AM
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#6
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Member Group: Members Posts: 85 Joined: 6-December 10 From: Meine, Germany Member No.: 12,458 Region Association: Germany |
I talked with a Bosch guy at the Techno Classica in Essen (Germany) who gave a short presentation about the D-Jet.
The Voltage from the ECU is 3V! Peter |
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| gifted914 |
Apr 18 2013, 03:53 PM
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#7
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middleagecrisis Group: Members Posts: 30 Joined: 17-April 13 From: Australia / Brisbane Member No.: 15,778 Region Association: Australia and New Zealand |
QUOTE(sofi2t81 @ Apr 19 2013, 12:48 AM) I talked with a Bosch guy at the Techno Classica in Essen (Germany) who gave a short presentation about the D-Jet. The Voltage from the ECU is 3V! Peter Thanks for the info. Peter (IMG:style_emoticons/default/beerchug.gif) |
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| Spoke |
Apr 18 2013, 06:07 PM
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#8
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Jerry Group: Members Posts: 7,158 Joined: 29-October 04 From: Allentown, PA Member No.: 3,031 Region Association: None
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QUOTE(sofi2t81 @ Apr 18 2013, 10:48 AM) I talked with a Bosch guy at the Techno Classica in Essen (Germany) who gave a short presentation about the D-Jet. The Voltage from the ECU is 3V! Peter Keep in mind that the 3V is output only when loaded with the injector. If one were to disconnect the injector, the output is actually 12V. There is a resistor between the switched 12V and the output. The resistor is about 6 ohms (6.15 ohms in P Anders website). The resistor limits the current through the injector and the voltage across the injector. The injector resistance is 2.67 ohms in P Anders website. One calculates the voltage across the injector to be a resistor divider between the internal 6.15 ohms and 2.67 ohm injector. So with the injector, the measured voltage would be : 12V x 2.67 / (2.67 + 6.15) = 3.6V. The injector current would be limited by the injector and internal resistances: 12V/(2.67 + 6.15) = 1.36 Amperes If you want to test an injector, use 12V with 6 ohms in series with the injector. The 6 ohm resistor does have to be a power type. Power calculated by I x I x R = 1.36A X 1.36A X 6 = 11 Watts. A 5W resistor would do since one would be pulsing the injector on and off to test (assumption). Sorry to get so technical. |
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