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jsayre914 |
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Speed Up !!! ![]() ![]() ![]() ![]() Group: Members Posts: 3,210 Joined: 10-February 08 From: Timonium MD 21093 Member No.: 8,696 Region Association: MidAtlantic Region ![]() |
I have 2 great hobbys, Porsche 914 and Car Stereo Sound.
I might not be faster than you guys, but I will have a very unique 914. I pulled all the stereo stuff out of my car, and I am starting all over. I just recieved my Kinetik batteries today. I got a HC1800 to replace my optima, the 1800 is rated at 1900 Amps. I also purchased a HC800 rated at 950 amps. I just found a upgrade 75amp alternator and a guy who will wind it to 120amp output to drop in place of the 55amp unit. I am going to be High Voltage! The totall draw on my stereo install will be about 120 amps at peak. I am keeping my amplifiers but building a different cabinet for the rear trunk. It will house both amps and the 800 power cell. I am ditching both capacitors that were in the trunk. The wiring will be upgraded from the alternator (Jeff Bowlsby) and I will run "0" guage from the batterys to hook togeather + to + and - to -. I will also add a few more heavy grounds from each battery to chasis and from chasis to engine. Yes there will be multiple inline fuses on the positive leads. (saftey first) I will update this thread with pics and progress as i go. (any comments) (IMG:style_emoticons/default/popcorn[1].gif) |
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Spoke |
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Jerry ![]() ![]() ![]() ![]() ![]() Group: Members Posts: 7,158 Joined: 29-October 04 From: Allentown, PA Member No.: 3,031 Region Association: None ![]() ![]() |
I believe to correctly specify the electrical system needed to drive the sound system and car, one would need to consider more about the characteristics of the music.
The peak current draw is one of the specs needed. The other is the RMS current which is the average current. Peak and RMS values are generally associated by the square root of 2 such that: RMS = Peak / sqrt(2) Also with music, it is a good design practice to allow at least a factor of 2 or more between the absolute peak and average peak. This is obvious if you have a power meter on your stereo and watch the peaks which usually occur on drum beats or the bass chords. So the average current would be: RMS = Peak /(2 x sqrt(2)) = 120/(2 x sqrt(2)) ~ 42Amps Consider also that even though all this power is available, there may be few times where the volume is cranked all the way to its maximum and the music amplitude is at the constant peak of the amplifier. |
SirAndy |
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Resident German ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() Group: Admin Posts: 42,207 Joined: 21-January 03 From: Oakland, Kalifornia Member No.: 179 Region Association: Northern California ![]() |
RMS = Peak /(2 x sqrt(2)) = 120/(2 x sqrt(2)) ~ 42Amps WOT: Speaking of Math, i was recently asked to help out a very well known wall street investment group with one of their main investment matrices. First of all, it's just one GIGANTIC excel spreadsheet. (IMG:style_emoticons/default/wacko.gif) But more importantly, it had a very peculiar hard-coded multiplication factor that was added to a lot of the cell formulas: sqrt(100) Anyone see anything wrong with that? (IMG:style_emoticons/default/lol-2.gif) Andy |
zymurgist |
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"Ace" Mechanic ![]() ![]() ![]() ![]() ![]() Group: Members Posts: 7,411 Joined: 9-June 05 From: Hagerstown, MD Member No.: 4,238 Region Association: None ![]() |
Kind of like E = mc^2 where c is a constant, therefore c^2 is a constant? |
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