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gifted914 |
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middleagecrisis ![]() Group: Members Posts: 30 Joined: 17-April 13 From: Australia / Brisbane Member No.: 15,778 Region Association: Australia and New Zealand ![]() |
G'day all.
Does anyone know the operating voltage and amps on the injector. I dont't thing it is straight 12 volts. Peter |
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sofi2t81 |
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#2
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Member ![]() ![]() Group: Members Posts: 85 Joined: 6-December 10 From: Meine, Germany Member No.: 12,458 Region Association: Germany ![]() |
I talked with a Bosch guy at the Techno Classica in Essen (Germany) who gave a short presentation about the D-Jet.
The Voltage from the ECU is 3V! Peter |
Spoke |
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#3
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Jerry ![]() ![]() ![]() ![]() ![]() Group: Members Posts: 7,158 Joined: 29-October 04 From: Allentown, PA Member No.: 3,031 Region Association: None ![]() ![]() |
I talked with a Bosch guy at the Techno Classica in Essen (Germany) who gave a short presentation about the D-Jet. The Voltage from the ECU is 3V! Peter Keep in mind that the 3V is output only when loaded with the injector. If one were to disconnect the injector, the output is actually 12V. There is a resistor between the switched 12V and the output. The resistor is about 6 ohms (6.15 ohms in P Anders website). The resistor limits the current through the injector and the voltage across the injector. The injector resistance is 2.67 ohms in P Anders website. One calculates the voltage across the injector to be a resistor divider between the internal 6.15 ohms and 2.67 ohm injector. So with the injector, the measured voltage would be : 12V x 2.67 / (2.67 + 6.15) = 3.6V. The injector current would be limited by the injector and internal resistances: 12V/(2.67 + 6.15) = 1.36 Amperes If you want to test an injector, use 12V with 6 ohms in series with the injector. The 6 ohm resistor does have to be a power type. Power calculated by I x I x R = 1.36A X 1.36A X 6 = 11 Watts. A 5W resistor would do since one would be pulsing the injector on and off to test (assumption). Sorry to get so technical. |
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