 WOT Max Power Load of an Amplifier, IX 406 6 channel x 40 watts = ???? when cranked |
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| Jeffs9146 |
 Mar 7 2008, 07:17 PM
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#1
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Ski Bum  Group: Members Posts: 4,062 Joined: 10-January 03 From: Discovery Bay, Ca Member No.: 128  |
I need to know the max load that an amp will put on a battery when turned up and all speakers loaded!
I know there are some very smart people here who might know how to figure this out, so give it your best! PS: This is the amp Kicker IX406 Thanks |
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| Spoke |
Mar 7 2008, 07:34 PM
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Jerry Group: Members Posts: 6,978 Joined: 29-October 04 From: Allentown, PA Member No.: 3,031 Region Association: None 
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Assuming you will power 6 channels @ 40W RMS,
Total power is 6 x 40W RMS = 240W RMS Change to peak power: 240W x sqrt(2) = 340W peak Assuming 100% efficiency of the amp (all power dissipated in speakers), total power input to amp is 340W peak Watts = Volts x Amps rearrange: Amps = Watts/Volts = 340W/14V = 24 Amps peak |
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| jsayre914 |
Mar 7 2008, 07:48 PM
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Speed Up !!! Group: Members Posts: 3,188 Joined: 10-February 08 From: Timonium MD 21093 Member No.: 8,696 Region Association: MidAtlantic Region |
QUOTE(Spoke @ Mar 7 2008, 08:34 PM)  Assuming you will power 6 channels @ 40W RMS, Total power is 6 x 40W RMS = 240W RMS Change to peak power: 240W x sqrt(2) = 340W peak Assuming 100% efficiency of the amp (all power dissipated in speakers), total power input to amp is 340W peak Watts = Volts x Amps rearrange: Amps = Watts/Volts = 340W/14V = 24 Amps peak (IMG:style_emoticons/default/agree.gif) lol |
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| Jeffs9146 |
Mar 7 2008, 08:12 PM
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#4
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Ski Bum Group: Members Posts: 4,062 Joined: 10-January 03 From: Discovery Bay, Ca Member No.: 128 |
Thanks!! I had just finished a Google search on that exact question and came up with the same info. I did forget about the peak part though!
Thanks (IMG:style_emoticons/default/piratenanner.gif) |
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| Scott Carlberg |
Mar 7 2008, 09:28 PM
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#5
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Porsche MOTORSPORTS Group: Members Posts: 1,595 Joined: 17-April 03 From: Modesto, Ca Member No.: 580 |
Jeff,
I asked my buddy who manages & does the install at a car stereo shop here in Modesto. Here's what he said: The Maximum amount of Current that the Amp can draw from the Battery is EQUAL to the amount/Size of the Fuse in the Amp. NO amp should be able to draw more current than the Fuse in the Amp. |
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| sww914 |
Mar 7 2008, 10:23 PM
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Advanced Member Group: Members Posts: 2,439 Joined: 4-June 06 Member No.: 6,146 Region Association: None |
(IMG:style_emoticons/default/agree.gif)
20 amp fuse X 12v = 240 watts 30 amp fuse X 12v = 360 watts The 5 channel US amps amplifier I have in my dually uses 3 30 amp fuses. It's plenty. |
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| Jeffs9146 |
Mar 8 2008, 01:38 AM
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#7
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Ski Bum Group: Members Posts: 4,062 Joined: 10-January 03 From: Discovery Bay, Ca Member No.: 128 |
QUOTE The Maximum amount of Current that the Amp can draw from the Battery is EQUAL to the amount/Size of the Fuse in the Amp. That part I knew! And most people dont know that if you put a smaller fuse in the ground wire it will also restrict the amp load as if it was a resistor. There is still a MAX load and the fuse is 10 - 20% above the rated amp max at full volume. |
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